Question

The density of the water in a swimming pool is 1000 kg / m3. The pool is 3 m deep. Calculate the pressure of the water at the bottom of the pool.

Answer 1

Explanation:

Pa = atmospheric pressure (look it up in units of N/m^2)

D = density of water (given as 1000 kg/m^3)

h = depth of water = 3m

g= acceleration of gravity = 9.8 m/s^2

At a depth of h (meters), the static pressure is

P(h) = Pa + Dgh

Plug in the numbers and get P(h) in units of N/m^2

# hope this helps u

Answer 2

Explanation:

ph=pa+dhg put in this forumula answer will come