Question

The density of two molarity solution of acetic acid is 1.02 gram per ml the molality of the solution is

Answer 1

Answer:

Hey mate......

Here's ur answer ::::::::

Given :

Solute — Acetic acid

Solvent — Water

Mol. Wt. of solute = 60 g/mol

Density (d) = 1.02 g/ml

.°. Wt. of solute = density * volume

since, volume =1L = 1000ml

Wt. of solute = 1.02*1000

= 1020g

Molality = Wt. of solute /mol. Wt. of solute * Wt. of solvent

Molality = 1020/60*18

= 1020/1080

= 0.94 molal.

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