Question

The density of water at 20 °C is 998 kg/m³ and it is 992 kg/m³ at 40 °C. The coefficient of volume expansion of water is .................. °C⁻¹. (A) 998 / (992×20) (B) 992 / (998×20) (C) 6 / (998×20) (D) 6 / (992×20)

Answer 1

Answer:

option D is correct

Explanation:

pls refer attachment

Answer 2

Answer:

(C) $\frac{6}{998 \times 20}$

Explanation:

As per the question,

We have been provided that,

The density of water at 20 °C = 998 kg/m³

The density of water at  40 °C = 992 kg/m³

Therefore,

Change in density, δv = (998 - 992) = 6

And

Change in temperature, δT= (40 - 20) = 20°C

Now,

The coefficient of volume expansion of water is given by

$\alpha_{v} = \frac{\delta v}{v} \times \frac{1}{\delta T}$

Put all the given values in this equation, we get

$\alpha_{v} = \frac{6}{998} \times \frac{1}{20}$

$\alpha_{v} =\frac{6}{998 \times 20}$

Hence, the correct option is (C).