Question

The density of water at 20 degree celsius 998 and at 40 degree celsius 992 cofficientof volume expansion of water is

Answer 1

Answer:

$3 \times {10}^{ - 4}$

Explanation:

If p is the final density & po is the initial density then,

$p = \frac{po}{1 + \gamma dt }$

Answer 2

Answer:

3 x 10-4

Given;

Density at T1 = 998

Density at T2 = 992

T1 = 20

T2 = 40

On applying the formula