Question

The density p of a piece of metal of a
mass
mand volume Vis given by p=-
if m= 350.45 + 0.01g, v= 125.32 +0.01
cm Find % error in p.
​

Answer 1

Answer:

hii

Explanation:

plzz subscribe my channel jiya khatri of youTube and when my channel will have 100 subscribers i will do question answer with you plzz support and for your question dm me on insta :) ;) !!!! plzz support me guys

Answer 2

Answer:

given = dm = 0.01 g and dN = 0.01 cm³

             m = 350.45          v= 125.32

to find = % error in p

solution =

               the error in mass  = dm / m = 0.01 / 350.45          

                                              = 2.8534

                  error in volume   =

                 dN/V = 0.1 / 125.32 = 7.9795

As density is a function of both mass and volume ,so we can do sum of the errors in the mass and volume ,

           dρ/ρ = dm /m +dN/v

                   = 2.8534  + 7.9795

                   =  10.8329

now % error in        ρ  = dρ/ρ × 100

                                ρ   =  10.8329 ×  100

                                     =  1083.29 %

          the final %  error is 1083.29%