Question

the density p of a piece of metal of mass m and volume v is given by the equation p=m/v...... if m = 375.32+ - 0.01 g and v= 136.41= - 0.01 cm3 . Find the % error in p

Answer 1

percentage error in density of the metal piece is 0.01%

it is given that,

mass of the metal piece, m = (375.32 ± 0.01) g

volume of metal piece, v = (136.41 ± 0.01) cm³

we know, density = mass/volume

so, percentage error formula will be ,

percentage error in p = % error in m + % error in v

= ∆m/m × 100 + ∆v/v × 100

= (0.01)/375.2 × 100 + 0.01/136.41 × 100

= 1/375.2 + 1/136.41

= 0.00266 + 0.00733

= 0.0099 ≈ 0.01%

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Answer 2

$\huge\bold\purple{Answer:-}$

it is given that,

mass of the metal piece, m = (375.32 ± 0.01) g

volume of metal piece, v = (136.41 ± 0.01) cm³

we know, density = mass/volume

so, percentage error formula will be ,

percentage error in p = % error in m + % error in v

= ∆m/m × 100 + ∆v/v × 100

= (0.01)/375.2 × 100 + 0.01/136.41 × 100

= 1/375.2 + 1/136.41

= 0.00266 + 0.00733

= 0.0099 ≈ 0.01%