Question

The department of Computer Science and Technology is conducting an International Seminar.

In the seminar, the number of participants in Mathematics, Science and Computer Science are

60, 84 and 108 respectively. The coordinator has made the arrangement such that in each room,

the same number of participants are to be seated and all of them being in the same subject.

Also, they allotted the separate room for all the official other than participants.(i) Find the total number of participants.

(ii) Find the LCM of 60, 84 and 108.

(iii)Find the HCF of 60, 84 and 108.

(iv)Find the minimum number of rooms required, if in each room, the same number of

participants are to be seated and all of them being in the same subject.

(v) Based on (iv) conditions, find the minimum number of rooms required for all the

participants and officials.​

Answer 1

Answer:

(i) Find the total number of participants.

Total number of participants = 60 + 84 + 108 = 252

(ii) Find the LCM of 60, 84 and 108.

LCM(60, 84, 108) = 3780

(iii)Find the HCF of 60, 84 and 108.

HCF(60, 84, 108) = 12

(iv)Find the minimum number of rooms required, if in each room, the same number of

participants are to be seated and all of them being in the same subject.

Minimum number of rooms required for all the participants = 252/12 = 21

(v) Based on (iv) conditions, find the minimum number of rooms required for all the

participants and officials.

Minimum number of rooms required for all = 21 + 1=22

PLEASE MARK IT BRAINLIEST

Answer 2

Given:

The department of Computer Science and Technology is conducting an International Seminar.

Mathematics = 60,

Science = 84,

and Computer Science = 108.

To Find:

(i). Find the total number of participants.

(ii). Find the LCM of 60, 84, and 108.

(iii). Find the HCF of 60, 84, and 108.

(iv). Find the minimum number of rooms required, if in each room, the same number of  participants are to be seated and all of them are on the same subject.

(v). Based on (iv) conditions, find the minimum number of rooms required for all the  participants and officials.​

Solution:

(i). Total number of participants = 60 + 84 + 108 = 252.

(ii). LCM(60, 84, 108) = 3780.

(iii). HCF(60, 84, 108) = 12.

(iv). The minimum number of rooms required for all the participants = 252/12 = 21.

(v). Minimum number of rooms required for all = 21 + 1 = 22.