Question

the depression in freezing point for 1M urea and 1M NaCL are in the ratio ?​

Answer 1

Explanation:

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Answer 2

Given:

Molarity of urea = 1M

Molarity of NaCl = 1M

To find:

The ratio of depression in freezing points

Calculation:

Depression in freezing point is given by the relation

  $\Delta T=i\times k_f\times m$    where i is  Van’t Hoff factor

  $\Delta T\propto i$

Urea is an organic compound and it cant be dissociated into ions. So for urea Van’t Hoff factor will be 1

NaCl will be dissolved into Na⁺ and Cl⁻ ions. So for NaCl Van’t Hoff will be 2

$\Delta T_{urea} : \Delta T_{NaCl}=i_{urea}\times k_f\times m:i_{NaCl}\times k_f\times m$

$\Delta T_{urea} : \Delta T_{NaCl}=1:2$

Final answer:

The ration of depression in freezing points is 1:2