Question

the depression in the freezing point of 0.01m aqueous solution of urea,sodium chloride and sodium sulphate is in the ratio of​

Answer 1

The depression in the freezing point of 0.01 m aqueous solution of urea,sodium chloride and sodium sulphate is in the ratio of​ 1:2:3

Depression in freezing point is given by the relation:

$\Delta T_f=i\times k_f\times m$

$\Delta T_f$ =  Depression in freezing point

i = Van'T Hoff factor  

$k_f$ = freezing point constant

m = molality

1. For 0.01 m urea

i= 1 as it is a non electrolyte and does not dissociate.

2. For 0.01 m $NaCl$

$NaCl\rightarrow Na^++Cl^-$

i= 2 as it is a electrolyte and dissociate to give 2 ions.

3. For $Na_2SO_{4}$

$Na_2SO_4\rightarrow 2Na^{+}+SO_4^{2-}$  

i= 3 as it is a electrolyte and dissociate to give 3 ions.

Thus as molality is same for all solutions, depression in freezing point is determined by vant hoff factor. As vant hoff factor for urea : $NaCl$ : $Na_2SO_4$ is in the ratio of 1: 2: 3, thus the depression in the freezing point will have also the ration of 1:2:3

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Answer 2

Answer:

Vant hoff factor(i) for urea : NaCl : Na2SO4

is in the ratio of 1: 2: 3

so, delta Tf = i × Kf × m

thus, delta Tf is directly proportional to i

Accordingly, the ratio of depression of freezing point is in the ratio of 1:2:3