Question

The depth d at which the value of acceleration due to gravity becomes \frac{1}{n}
times the value at the surface, is [R = radius of the earth] [MP PMT 1999; Kerala PMT 2005]
A) \frac{R}{n} B) R\,\left( \frac{n-1}{n} \right) C) \frac{R}{{{n}^{2}}} D) R\,\left( \frac{n}{n+1} \right)

Answer 1

The depth d at which the value of acceleration due to gravity becomes \frac{1}{n} times the value at the surface, is - D.