Social Sciences, asked by ankitvirat456, 26 days ago

The depth of water on the Thada lake of Arghakhanchi district is 8m, find the pressure exerted by water at the bottom of it

Answers

Answered by shobhadevi66744

0

Explanation:

h=8m

rho=10^3kg/m^3

g=10m/s^2 (assumption)

P=h×rho ×g

=8×10×1000

=80000Pa

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