The depth of water on the Thada lake of Arghakhanchi district is 8m, find the pressure exerted by water at the bottom of it
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Answer:
Height (h)=6m,
density=1000kgm
−3
,
g=10ms
−2
,Pressure=?
P=hdg
=6×1000×10Pa
=60000Pa
=6×10
4
Pa.
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