the derivate of inverse function of f:|0,1| ➡️R; f(x)=xe^xat x = 0.5 is
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g is the inverse of f, the derivative of f(x) is 1/g'(f(x)), not 1/f'(x). In this case, g'(x)=e^x, so the derivative of ln(x) is 1/[e^(ln(x))]=1/x.
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