The derivative of 3 cot x + 5 cosec x W. r. t. xis:
(A) 3 cosec2x - 5 cosec x cot x
(B) - 3 cosecx - 5 cosec x cot x
(C) - 3 cosec2x + 5 cosec x cotx
(D) 3 cosec2x + 5 cosec x cotx
Answers
Answer:
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Step-by-step explanation:
It is possible to find the derivative of trigonometric functions.
Here is a list of the derivatives that you need to know:
d (sin x) = cos x
dx
d (cos x) = –sin x
dx
d (sec x) = sec x tan x
dx
d (cosec x) = –cosec x cot x
dx
d (tan x) = sec²x
dx
d (cot x) = –cosec²x
dx
One condition upon these results is that x must be measured in radians.
Applying the Chain Rule
The chain rule is used to differentiate harder trigonometric functions.
Example
Differentiate cos³x with respect to x.
Let y = cos³x
Let u = cos x
therefore y = u³
dy = 3u²
du
du = -sin x
dx
dy = du × dy
dx dx du
= -sin x × 3u²
= -sin x × 3cos²x
= -3cos²x sin x
Answer:
(B) -3cosec²x-5cosecxcotx
Step-by-step explanation:
d/dx(3cotx)+d/dx(5cosecx)
= -3cosec²x-5cosecxcotx