Physics, asked by salonii12, 1 year ago

The derivative of f(x) = 3x^2 + 2x + 4 w.rt. x is

Answers

Answered by pr456
0

Answer:

The answer is

=

2

(

1

+

ln

x

)

x

2

x

Explanation:

We need

(

u

v

)

'

=

u

'

v

+

u

v

'

y

=

x

2

x

ln

y

=

ln

(

x

2

x

)

ln

y

=

2

x

ln

x

Differentiating wrt

x

1

y

d

y

d

x

=

2

(

x

1

x

+

1

ln

x

)

d

y

d

x

=

2

(

1

+

ln

x

)

y

d

y

d

x

=

2

(

1

+

ln

x

)

x

2

x

Answered by Anonymous
29

hey mate

The derivative of f(x) = 3x^2 + 2x + 4 w.rt. x is

so,

d/dx{f(x)}=d/dx(3x^2 + 2x + 4)

=3×2 x +2 +0

= 6x + 2.

I hopes its helps u.

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@abhi.


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