The derivative of f(x) = 3x^2 + 2x + 4 w.rt. x is
Answers
Answered by
0
Answer:
The answer is
=
2
(
1
+
ln
x
)
x
2
x
Explanation:
We need
(
u
v
)
'
=
u
'
v
+
u
v
'
y
=
x
2
x
ln
y
=
ln
(
x
2
x
)
ln
y
=
2
x
ln
x
Differentiating wrt
x
1
y
d
y
d
x
=
2
(
x
⋅
1
x
+
1
⋅
ln
x
)
d
y
d
x
=
2
(
1
+
ln
x
)
y
d
y
d
x
=
2
(
1
+
ln
x
)
x
2
x
Answered by
29
hey mate
The derivative of f(x) = 3x^2 + 2x + 4 w.rt. x is
so,
d/dx{f(x)}=d/dx(3x^2 + 2x + 4)
=3×2 x +2 +0
= 6x + 2.
I hopes its helps u.
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