The derivative of log (sin(logx) (x > 0) khhfd
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Answer:
y = sin(log x)
dy/dn = d/dx .(sin log x) = cos (log x) . d/dx . (log x)
= cos (log x) . 1/x . d/dx (x)
= (cos (log x))/ x . 1
= (cos (log x))/x
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