Question

The derivative of log (sin(logx) (x > 0) ​kjj

Answer 1

Explanation:

स्पष्टीकरण: उत्तर: (cos (लॉग x)) / (x। Sin (लॉग x)) चरण - द्वारा - चरण स्पष्टीकरण: Let: y = log (sin (log x)), x> 0 # लॉग x = log_e x = ln x हम जानते हैं: => (x में) '= 1 / x => y' = 1 / sin (log x)। (sin (log x)) '=> y' = 1 / sin (log x)। (cos (लॉग x))। (log x) '=> y' = 1 / sin (लॉग x)। (cos (लॉग x))। 1 / x => y = (cos (log x)) / (x। Sin (लॉग x)) Lancamaatrecuired aneworl

♛ ꜱᴏ ᴜ ɪꜱ ᴇQᴜᴀʟ ᴛᴏ ᴛʜᴇ ɢᴏʟᴅᴇɴ ʀᴀᴛɪᴏ! ɴᴏᴡ ᴡᴇ ʜᴀᴠᴇ ᴏɴᴇ ꜱᴛᴇᴘ ʟᴇꜰᴛ: ᴛᴏ ꜱᴏʟᴠᴇ ꜰᴏʀ x. ᴡᴇ ᴄᴀɴ ᴅᴏ ᴛʜᴀᴛ ᴡɪᴛʜ ᴛʜᴇ ʜᴇʟᴘ ᴏꜰ ᴛʜᴇ ɴᴀᴛᴜʀᴀʟ ʟᴏɢᴀʀɪᴛʜᴍ. ♛

Answer 2

Answer:

refer the attachment :)Explanation: