The derivative of log (sin(logx) (x > 0) kjj
Answers
Answered by
2
Answer:
y = sin(log x)
dy/dn = d/dx .(sin log x) = cos (log x) . d/dx . (log x)
= cos (log x) . 1/x . d/dx (x)
= (cos (log x))/ x . 1
= (cos (log x))/x
Answered by
0
refer the attachment :)
Attachments:
Similar questions