Question

The derivative of log (sin(logx) (x > 0) ​kjj

Answer 1

Answer:

y = sin(log x)

dy/dn = d/dx .(sin log x) = cos (log x) . d/dx . (log x)

= cos (log x) . 1/x . d/dx (x)

= (cos (log x))/ x . 1

= (cos (log x))/x

Answer 2

refer the attachment :)