The derivative of log (sin(logx) (x > 0)
Mbxa
Answers
Step-by-step explanation:
Explanation:
Explanation:
Answer:
( cos ( ㏒ x ) ) / ( x . sin ( ㏒ x ) )
Step-by-step explanation:
Let :
y = ㏒ ( sin ( ㏒ x ) ) , x > 0
# ㏒ x = ㏒_e x = ㏑ x
We know :
= > ( ㏑ x )' = 1 / x
= > y' = 1 / sin ( ㏒ x ) . ( sin ( ㏒ x ) )'
= > y' = 1 / sin ( ㏒ x ) . ( cos ( ㏒ x ) ) . ( ㏒ x )'
= > y' = 1 / sin ( ㏒ x ) . ( cos ( ㏒ x ) ) . 1 / x
= > y' = ( cos ( ㏒ x ) ) / ( x . sin ( ㏒ x ) )
Hence we get required answer!
integrate the function:
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Let 2-x=t
differentiating both sides w.r.t.x
Integrating the function w.r.t.x
Put the value of 2-x=t and dx=-dt
It is the form of :
∴ Replace a by 1 and x by t we get
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