Math, asked by akhi79, 3 months ago

The derivative of tan-¹ x w.r.t. (1 + x²)​

Answers

Answered by senboni123456
1

Step-by-step explanation:

let \:  \: u =  \tan ^{ - 1} (x)  \:  \: and \:  \: v = 1 +  {x}^{2}  \\

 \implies \frac{du}{dx}  =  \frac{1}{1 +  {x}^{2} }   \:  \: and \:  \:  \frac{dv}{dx}  = 2x \\

 \implies \frac{du}{dv}  =  \frac{1}{2x(1 +  {x}^{2} )}  \\

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