Question

the derivative of xlogx-x is​

Answer 1

Answer:

Ah it's too simple dear....

xlogx - x.....

Derivative is :- logx.....

Answer 2

Answer:

$f(x) = xlogx - x \\ \\ f'(x) = x \frac{d}{dx} (logx ) + logx \frac{d}{dx}(x ) - x \\ \\ \: \: \: \: \: \: = x (\frac{1}{x} ) + logx(1) - 1 \\ \\ \: \: \: \: \: \: \: = 1 + logx - 1 \\ \\ \: \: \: \: \: \: \: = logx$