Question

The derivative of y if y=(3x+2)(2x-1)​

Answer 1

Explanation:

Here, u=3x+2, v=2x−1.

Differentiating both sides, we get

dydx=ddx[3x+2][2x−1]

Using product rule, we get

d[uv]dx=udvdx+vdudx

dydx=[3x+2]ddx[2x−1]+[2x−1]ddx[3x+2]

=[3x+2][2]+[2x−1]3

=6x+4+6x−3=12x+1