Question

The derivatives of log ( 2x + 1 ) w.r.t. x, at x = 2 is​

Answer 1

Step-by-step explanation:

$2x + 1$

Given

X = 2

Now put

$2 \times 2 + 1$

$4 + 1$

$5$

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Answer 2

$\large{ \underline{ \underline{ \bigstar \: \: \: \: \: { \pmb{ \sf{Solution \: : }}}}}}$

$\sf\dashrightarrow \frac{d}{dx}f(x) = \frac{d}{dx} \bigg(\log(2x + 1) \bigg)$

$\dashrightarrow \sf \frac{d}{dx} f(x) = \frac{1}{2x + 1} \times 2$

$\dashrightarrow \sf \frac{d}{dx} f(x) \bigg| _{x = 2}= \frac{2}{2(2) + 1}$

$\dashrightarrow \frak \blue{ \frac{d}{dx} f(x) \bigg| _{x = 2}= \frac{2}{5} }$

$\large{ \underline{ \underline{ \bigstar \: \: \: \: \: { \pmb{ \sf{Conception \: : }}}}}}$

$\dashrightarrow \sf \frac{d}{dx} fog(x) = f'(x) × g'(x)$

$\sf \dashrightarrow \frac{d}{dx} \bigg(\log(x) \bigg)= \frac{1}{x}$