The derivatives of sin inverse[2x/1+x^2] with respect to cos inverse [1-x^2/1+x^2] is
Answers
Answered by
47
Hello Yuvi,
Since ,
sin^-1 {2x/(1+x^2)} =
=cos^-1 {(1-x^2)/(1+x^2).
Hence,derivative of sin^-1 {2x/(1+x^2)}
w.r.t. cos^-1{(1-x^2)/(1+x^2)}will be 1answer ...
Thank you! !
Answered by
12
sin^-1 {2x/(1+x^2)} =cos^-1 {(1-x^2)/(1+x^2).
Hence,derivative of sin^-1 {2x/(1+x^2)}
w.r.t. cos^-1{(1-x^2)/(1+x^2)}will be answer ...
(^‿^✿)
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