Question

The derivatives of sin inverse[2x/1+x^2] with respect to cos inverse [1-x^2/1+x^2] is

Answer 1

Hello Yuvi,

Since ,

sin^-1 {2x/(1+x^2)} =

=cos^-1 {(1-x^2)/(1+x^2).

Hence,derivative of sin^-1 {2x/(1+x^2)}

w.r.t. cos^-1{(1-x^2)/(1+x^2)}will be 1answer ...

Thank you! !

Answer 2

sin^-1 {2x/(1+x^2)} =cos^-1 {(1-x^2)/(1+x^2).

Hence,derivative of sin^-1 {2x/(1+x^2)}

w.r.t. cos^-1{(1-x^2)/(1+x^2)}will be answer ...



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