Question

the derive the equation for distance covered by a uniform accelerated body in nth sec. of its motion by calculus. a body covers 12m in 2nd second and 20m in 4th second of its motion. find the velocity after 10 sec.​

Answer 1

Answer:

Explanation:

First of all, the distance covered in the last t seconds of ascent is equal to the distance covered in the first t seconds of descend. S=0.5*g*t*t , where g is the acceleration due to gravity and t is the time. In the above formula, u is the initial velocity.The distance travelled by a body in the nth second is given by the expression (2+3n).