Question

The diagnal of square is 20m find its area (take√2=1.414​

Answer 1

Answer:

Step-by-step explanation:

let x be one side of a square,

using Pythagoras theorem

x² + x² = 20

2x² = 20

x² = 10

x = 3.2m

Answer 2

Step-by-step explanation:

$\huge\underline\bold\pink{Answer: - }$

$\sqrt{2} a = 20 \\ = > a = \frac{1}{ \sqrt{2} } \times 20 \\ = > \: \frac{20 \times \sqrt{2} }{ \sqrt{2 } \times \sqrt{2} } - - - - - (by \: rationalisation \: of \: denominator) \\ = > \frac{20 \times \sqrt{2} }{2} \\ = > 10 \sqrt{2 } - - -( by \: reducing \: into \: simplest \: form.) \\ = > a = 10 \sqrt{2} \\ now \: area = {a}^{2} \\ = > {(10 \sqrt{2}) }^{2} \\ = > 200 {m}^{2} \: (ans)$

$\bold\pink{Some \: inportant \: points \: to \: be \: noted: -}$

Diagonal of a square =$\sqrt{2} a$,where a is the side of the square.

Area of square = ${side}^{2}$

$\underline\bold\pink{Done \: by \: Aritra \: Kar: - }$