The diagnoals of a rectangle ABCD intersect at O if angle BOC is equal to 70 degree find angle ODA
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hey mate here is your answer .
given .abcd is a rectangle .o is the interesting point angle boc is equal to 70 °
so if angle boc is 70 ° then angle aod is also 70° as (v.o.a)
then as the rectangle 's one of the property is that the bisect each other than
in triangle aod ,ad is equals to ab so ,angle oda is equal to angle oad so let take the angles as X
now in triangle aod
angle oad+ angle ado+ angle dao=180 (angle sum property )
X+X+70°=180°
2x=180-70
2x=110
X=55
so measure of angle oda is 55 degree
hope it may help u
given .abcd is a rectangle .o is the interesting point angle boc is equal to 70 °
so if angle boc is 70 ° then angle aod is also 70° as (v.o.a)
then as the rectangle 's one of the property is that the bisect each other than
in triangle aod ,ad is equals to ab so ,angle oda is equal to angle oad so let take the angles as X
now in triangle aod
angle oad+ angle ado+ angle dao=180 (angle sum property )
X+X+70°=180°
2x=180-70
2x=110
X=55
so measure of angle oda is 55 degree
hope it may help u
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