Question

the diagnol of a quadrilateral shaped field is 24 m and the remaining opposite verticales are 8m and 13m find the area of the field​

Answer 1

Answer:

Let the quadrilateral be ABCD then BD divides the quadrilateral into two triangles.

Area of ABCD=Area of triangle ABD +Area of triangle BCD

Area of triangle ABD=\frac{1}{2}\times base\times height

2

1

×base×height

=\frac{1}{2}\times24\times13

2

1

×24×13

=156m^2156m

2

Area of traingle BCD=\frac{1}{2}\times base\times height

2

1

×base×height

=\frac{1}{2}\times24\times8=

2

1

×24×8

=96\ m^2=96 m

2

Area of field=156+96

==252m^2=252m

2