Question

The diagnol of a square is 5√2m. Find its area and perimeter.

Answer 1

$\huge\mathcal{Heya}$

Given :-

Diagonal of a square = 5√2 m

Solution :-

As we know that,

Diagonal of a square = √2 × side

Also,

Diagonal = 5√2 m

•°•

√2 × Side = 5√2 m

Side = 5 m

Now,

Perimeter of a square = 4 × Side

=> 4 × 5

=> 20 m

Area of a square = (Side)²

=> (5)²

=> 25 m²

$\huge\mathbb{Hope \ this \ helps.}$

Answer 2

Diagonal of Square = √2(value of square side)

5√2= √2a where a is length of square

a= 5m

area of square = a²= 5²=25m².....ans(1)

perimeter of square =4a=4(5)=20m.....ans(2)