Question

the diagnol of a square is 8cm. what is it's area​

Answer 1

Hey, here is ur ans

Here, ABCD is a square.

Here, ABCD is a square.Let AB=BC=CD=AD=a

[ All sides of square are equal ]

[ All sides of square are equal ]⇒ AC=8 cm [ Given ]

[ Given ]In right angled triangle ABC△

[ Given ]In right angled triangle ABC△⇒ (AC)^2=(AB)^2+(BC)^2

[ By Pythagoras theorem ]

⇒ (8)^2=a^2+a^2

=>64=2a^2

⇒a^2=32a

⇒a^2=32a ⇒ Area of a square =a^2=32 cm

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