Question

The diagnols of a rectangle ABCD intersect at O. If angle BOC=68*, find angle ODA

Answer 1

=> OA = OD

=> angle ODA = angle OAD = x

(Angle opposite equal sides)

Thus in ∆AOD, by angle sum property

=> x + x + 68° = 180°

=> 2x = 112°

=> x = 56°

Thus Angle ODA = 56