the diagnols of a rhombus ABCD at O .If AC=10cm BD=24cm find the length of its side
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All sides of rhombus = 10 cm
Step-by-step explanation:
As AC = 16 cm, so OA = 8 cm (because diagonals of a rhombus bisect each other)
also BD = 12 cm, so OB = 6 cm
Now in right triangle AOB
AB^2 = OA^2 + OB^2
AB^2 = 8^2 + 6^2
AB^2 = 64 + 36
AB^2 = 100
AB = root 100
AB = 10.
therfore side of rhombus = 10 cm
and all sides of rhombus are equal.
so AB = BC = CD = AD = 10 cm.
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