the diagnols of a rhombus are 24 cm and 10 cm find the sides of the Rhombus in cm square
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diagonals are perpendicular bisectors of each other
so it forms right angle triangle
so 24÷2=12&10÷2=5
(side )^2=(12)^2+(5)^2
=144+25
=169
by taking square root
side=13
hope it helps you
plz mark brainliest
so it forms right angle triangle
so 24÷2=12&10÷2=5
(side )^2=(12)^2+(5)^2
=144+25
=169
by taking square root
side=13
hope it helps you
plz mark brainliest
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