Question

The diagnols of a rhombus are 7.5 cm qnd 12 cm.Find its area?​

Answer 1

Given,

$\text{First diagonal of Rhombus} \: {(d_1) = 7.5cm}$

$\text{Second diagonal of Rhombus} \: {(d_2) = 12cm}$

To find,

$\text{The Area of Rhombus}.$

Solution,

$\boxed{\text {Area of Rhombus} = { \frac{1}{2} × {d_1 × d_2}}}$

$\implies{\text {Area of Rhombus} = { \frac{1}{ \cancel{2}} × {7.5cm × \cancel{12}cm}}}$

$\implies\text {Area of Rhombus} =7.5cm × 6cm$

$\implies \red{\boxed{\textbf {Area of Rhombus} = \bf45 \textbf{cm}^{2}}}$

Final Answer,

• $\pink{\boxed{\textbf {Area of Rhombus} = \bf45 \textbf{cm}^{2}}}$

Hope you get your AnSwEr

Answer 2

Given : Diagonal¹ of rhombus = 7.5 cm and Diagonal² of rhombus = 12 cm.

To Find : Find the Area of Rhombus ?

_______________

Solution : Let the area of rhombus be x cm.

$~$

$\dag ~\underline{\frak{\pmb{As ~we ~know ~that~:}}}$

• $\boxed{\frak{\pmb{Area~of~ Rhombus~=~\dfrac{1}{2}~×~d_{1}~×~d_{2}}}}$

$~$

$\dag ~\underline{\frak{\pmb{According~to~the~given~question~:}}}$

$~$

$\qquad{\sf:\implies{Area~of~ Rhombus~=~\dfrac{1}{2}~×~d_{1}~×~d_{2}}}$

$\qquad{\sf:\implies{Area~of~ Rhombus~=~\dfrac{1}{\cancel{2}}~×~7.5cm~×~\cancel{12}cm}}$

$\qquad{\sf:\implies{Area~of~ Rhombus~=~7.5cm~×~6cm}}$

• ${\underline{\boxed{\frak{\pink{\pmb{Area~of~Rhombus~=~45cm^2}}}}}}$★

$~$

Hence,

• ${\sf{The~\bf{Area}~\sf{of}~\bf{Rhombus}~\bold{\pmb{\underline{45cm^2}.}}}}$

$~$

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More Information :

• ${\rm\leadsto{\pmb{Area~of~rhombus~=~\dfrac{1}{2}~×~d_{1}~×~d_{2}}}}$

• ${\rm\leadsto{\pmb{Area~of~ parallelogram~=~Base~×~Heigt}}}$

• ${\rm\leadsto{\pmb{Area~of~square~=~Side~×~Side}}}$

• ${\rm\leadsto{\pmb{Area~of~ rectangle~=~ Length~×~ Height}}}$

• ${\rm\leadsto{\pmb{Area~of~ triangle~=~ \dfrac{1}{2}~×~ Base~×~ Height}}}$