Question

the diagnols of a rhombus measure 16 and 30 find perimeter ​

Answer 1

Answer:

Here you go ............

Step-by-step explanation:

Length of the side of a rhombus = square root of sum of the squares of the diagonals divided by two

L = $\sqrt{d1^{2}+d2^{2} }$}/2

L = √(256+900)/ 2

L = √1156 / 2

L = 34 / 2

L = 17

Perimeter = 4L = 4(17) = 68

Hope it helps you.....

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