the diagnols of arohmbus areof lengths 16 and 12 cm
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Let AC=12cmAC=12cm
BD=16cmBD=16cm
BO=12BO=12BDBD
=8cm=8cm
AD=12AD=12AC=6cmAC=6cm
Now in Right ΔAOB ΔAOB
AB2=AO2+OB2AB2=AO2+OB2
=62+82=62+82
=36+64=36+64
=100=100
=102=102
AB=10cmAB=10cm
The length of each of its sides =10cm=10cm
Answer : 10cm
BD=16cmBD=16cm
BO=12BO=12BDBD
=8cm=8cm
AD=12AD=12AC=6cmAC=6cm
Now in Right ΔAOB ΔAOB
AB2=AO2+OB2AB2=AO2+OB2
=62+82=62+82
=36+64=36+64
=100=100
=102=102
AB=10cmAB=10cm
The length of each of its sides =10cm=10cm
Answer : 10cm
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