the diagnols of rhombus are 12cm and 16cm find the perimeter of rhombus
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Answered by
4
Solution :
Let d1,d2 are Two diagonals
of a Rhombus .
d1 = 12cm ,
d2 = 16cm
Side of the Rhombus ( a )
= √ (d1/2 )² + ( d2/2 )²
= √( 12/2 )² + ( 16/2 )²
= √ 6² + 8²
= √36 + 64
= √100
= √10²
= 10
a = 10
Therefore ,
Perimeter ( P ) = 4a
= 4 × 10
= 40 cm
••••
Answered by
2
Answer:
Step-by-step explanation:
P=4a
a=root p square + q square /2
2x under root p square+q square
2x √16sq+√12sq
2x20=40cm
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