Question

the diagnosis of a rombhus measure 16 cm and 30 cm . find its perimeter

Answer 1

Heya !!



Let ABCD is a rhombus , in which AD and BC are it's two diagonals.




Let AD = 16 cm and BC = 30 cm.






Therefore,





OA = 1/2 × AD = 1/2 × 16 = 8 cm.



And,


OB = 1/2 × BD = 1/2 × 30 = 15 cm.




In right triangle OAB,






AB² = OA² + OB²



AB² = (8)² + (15)²



AB² = 289



AB = √289 = 17 cm





Therefore,



Perimeter of rhombus ABCD = 4 × 17 = 68 cm.