The diagonal AC and BD of a parallelogram ABCD intersect each other at point O.If angle DAC=30° and angle AOB=70°,then what is the measure of angle DBC?
Answers
Answered by
4
Answer:
Draw the picture. I'm not smart enough to do it without being able to look at it.
If angle AOB = 70, the opposite angle, DOC, is also 70. These two angles total 140, so the othe two central angles, BOC and AOD, total 220 (360 - 140), and each one = 110. Since angle DAC = 32, angle ACB also = 32. All the interior angles of a triangle = 180. Adding the two known angles (BOC = 110, OCB = 32) = 142. Subtracting 142 from 180 = 32.
Angle DBC = 32.
As I write this the Big 10 is 6 and 0
if u like so please make me as brainlist please please. i will tell you all the questions.please make me as brainlist please please.
thanku...
Step-by-step explanation:
Similar questions