The diagonal AC and BD of a parallelogram ABCD intersect at O If p is the mid point of AD prove
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Answer:
proved
Step-by-step explanation:
Make a mid point of BC and name it E. As we know that opposite sides of a ||gm are equal. So their mid points are also at the same distance from each other. So we can say that AP=BE.
In triangle AOP and BOE
AP=BE (proved above)
AO=BO (as o is the mid of both the diagonals AC and BD
And,angle O is common
Therefore, triangle AOP is congurent to BOE (by SAS congurency rule)
Which makes PO=OE(cpct)
Therefore PE =AB and AP=BE,which makes them parallel.☺
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