The diagonal AC and BD of a parallelogram ABCD intersect at O.if OA=2x-3,OC=y+4,OB=x+3 and OD=2y-1, find the values of x and y.
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Answer:
x = 6 ; y = 5
Step-by-step explanation:
Diagonals of a parallelogram, bisect each other.
Here, O is the point of intersection.
So, OA = OC and OB = OD
2x - 3 = y + 4
2x - y = 7...(i) and
x + 3 = 2y - 1
x - 2y = -4....(ii)
Solving equations (i) and (ii) using (i) - 2×(ii) we get,
2x - y - 2x + 4y = 7 + 8
3y = 15
y = 5 and
x - 2×5 = -4
x = 6
Hence, x = 6 and y = 5.
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