Question

The diagonal AC and BD of a rhombus ABCD meet at O . If AC=10 cm and BD =24 cm .Find sin angle OAD .

Answer 1

Answer:

THE REQUIRED ANSWER IS 12 /13

Step-by-step explanation:

We know that for a Rhombus diagonal bisects each other at right angle

Now by the given condition

AC = 10 cm

BD = 24 cm

So

OA = 5cm

OD = 12 cm

Using law of Geometry

AD = √5² + 12² = √25 + 144 = √169 = 13

SO

Sin OAD = OD / AD = 12/13

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