Question

The diagonal ac of a parellogram ABCD bisects angle a show that it bisects abgle c also and ABCD is a rhombus
Has

Answer 1

Answer:

Step-by-step explanation:

∠BAC = ∠ACD and ∠DAC = ∠BCA

but, ∠BAC = ∠DAC (given)

⇒∠ACD = ∠BCA

also ∠A = ∠C

In ΔADC,

∠DAC = ∠ACD (proven)

⇒ it is isoceles Δ

⇒ AD = DC

now in a parallelogram ABCD, adjacent sides are equal

⇒ ABCD is a rhombus