Question

The diagonal AC of a quadrilateral ABCD is 6 cm and the perpendiculars, BM from the vertex B is

3 cm and DN from D is 5 cm, dropped on the same diagonal. Find the area of the quadrilateral

ABCD.​

Answer 1

Answer:

$24 \: {cm}^{2}$

Step-by-step explanation:

Ara of the quadrilateral ABCD =

$\frac{1}{2} (AC \times BM )+ \frac{1}{2} (AC \times DN)$

=

$\frac{1}{2} \times 6 \times 3 \: + \: \frac{1}{2} \times 6 \times 5$

=

$9 \: + 15 \: = 24 \: {cm}^{2}$