The diagonal Ac of a quadrilateral ABCD is 6cm and the perpendiculars, BM from vertex B is 3cm and DN from D us 5cm, dropped on the same diagonal. Find the area of quadrilateral ABCD.
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Answer:
AC -6cm
BM -3cm
DN -5cm
In ∆ABC = 1/2 ×AC×BM
= 1/2×6×3 - 9
In ∆ADC = 1/2 ×AC×DN
= 1/2 ×6×5 = 15
Area of quadrilateral ABCD = ∆ADC
= 9+15
=24 cm 2
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