the diagonal AC of parallelogram ABCD bisects Angle BAD show that quadrilateral ABCD is a rhombus
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trianlge ADC is congruent to triangle ABC
AD=CB(opp sides)
CA=CA(common)
DC=BA(opp sides)
ADC is congruent to CBA
angleACD=angleCAB
angle DAC = angle BCA
angle CAB =angle DAC
andle ACD = angle BCA
AC BISECT C
SO
ANGLE ACD = ANGLE CAD
AD=CD
AB=BC=CD=AC
ABCD IS A RHOMBUS
AD=CB(opp sides)
CA=CA(common)
DC=BA(opp sides)
ADC is congruent to CBA
angleACD=angleCAB
angle DAC = angle BCA
angle CAB =angle DAC
andle ACD = angle BCA
AC BISECT C
SO
ANGLE ACD = ANGLE CAD
AD=CD
AB=BC=CD=AC
ABCD IS A RHOMBUS
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