Question

The diagonal and length of a rectangle are 10cm and 8cm.find its perimeter and area

Answer 1

Answer:

By using the pythagoras theorem , we get Width of rectangle =

$\sqrt100 - 64$

= 6cm

Step-by-step explanation:

perimeter of rectangle = 2×(8+6)

=28cm ans

area of rectangle = 8×6

=48cm^2 Ans

Answer 2

Answer:

Step-by-step explanation:

Diagonal of a rectangle=10 cm

Length of a rectangle =8 cm

Now by phythagorus theorm

Hypotenuse=10 cm

Base =8 cm

Height ⇒ !

hy² ⇒ b²+h²

10²⇒ 8² +h²

h²⇒100-64

h²⇒36

h⇒√36

h⇒6

Base ⇒6 cm

Perimeter⇒2(l+b)

                ⇒2(8+6)

                 ⇒2×14

                  ⇒28 cm²

Area⇒L×B

        ⇒8×6

        ⇒48 cm²

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