Question

The diagonal of a cube is
$8 \sqrt{3}$
Find Its Surface area​

Answer 1

Answer:

let length of cube is L

so diagonal = 2L^2 + L^2 = 3L^2

A.Q.T. 3L^2 = (8√3)^2

L = 8

Now Surface Area = L^2 = (8)^2 = 64

hope it helps