The diagonal of a field in the shape of a quadrilateral is 20m and the offsets to the diagonal
are 8m and 9m. Find its area.
Answers
Answered by
0
Considering parallelogram as two symmetrical triangles with sides 40,60,80 metres
we have
Area of triange= Sqrt(s(s-40)(s-60)(s-80))
s=(40+60+80)/2=90
So area= Sqrt(90*(90-40)*(90-60)*(90-80))
=Sqrt(90*50*30*10)
=300*Sqrt(15)
Since there are two such triangle
Total area of parallelogram =2*300*Sqrt(15)
=600*Sqrt(15) m^2
Therefore the answer is 6)
Answered by
0
Answer:
The diagonal of a quadrilateral is 16 m. If the offsets are 6 m and 8 m, the area of the quadrilateral = (16/2)(6+8) = 112 sq m. hope this helps
Step-by-step explanation:
Similar questions