Question

The diagonal of a
parallelogram ABCD interscet
at O. If angle BOC=90degree
and angle BDC=50degree then
angle OAB=. plz guys help me ​

Answer 1

Answer:

40°

Step-by-step explanation:

CDO=ABO. (Alternate interior angle)

#ABO=50°. -----(1)

COB=AOB. (Both angles lies on same line)

#AOB=90°. -----(2)

SUM OF ALL ANGLE OF TRIANGLE IS 180°

So, ABO+AOB+OAB= 180°

OAB=180°-140°

OAB=40°

Answer 2

Answer:

90°

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